Balance the following chemical reactions while we are first getting started writ

Question

Balance the following chemical reactions while we are first getting started write the coefficient number in front of each compound, even if the number is 1. ________ Na (s) + _______ N_2(g) rightarrow _______ NaN_3 _____ C_2H_4O_2 + ____ O_2 rightarrow CO_2 + ___ H_2O _______ V_2O_5 + ___ CaS rightarrow _____ CaO + ________ V_2S_5 ____ S_8 + ____ O_2 rightarrow ________ SO_2 ______ H_2O_2 rightarrow _______O_2 + ______ H_2O ____ Al_2O_3 + ___ Fe rightarrow ___ Fe_3O_4 + ___ Al __ S + ___ HNO_3 rightarrow ___ H_2SO_4 + NO_2 + ___ H_2O

Explanation / Answer

Solution:- (1) The given equation is....

Na(s) + N2(g) -----> NaN3

to balance N we need to multiply N2 by 3 and NaN3 by 2.

Na(s) + 3N2(g) -----> 2NaN3

Now to balance Na we need to multiply Na on left side by 2 and the balanced equation would be...

2Na(s) + 3N2(g) -----> 2NaN3

(2) C2H4O2 + O2 -----> CO2 + H2O

This is a combustion equation and for balancing these equations we balance the carbon first, then hydrogen and finally oxygen.

Here left side has two carbons and right has one carbon so for balancing this we need to multiply CO2 by 2.

C2H4O2 + O2 -----> 2CO2 + H2O

now, left side has 4 hydrogen and right side has 2 hydrogen, so to balance hydrogen we need to multiply H2O by 2.

C2H4O2 + O2 -----> 2CO2 + 2H2O

Finally we will balance oxygen. Right side has six oxygen and left side has four oxygen. So, to balance oxygen we need to multiply O2 by 2.

1C2H4O2 + 2O2 -----> 2CO2 + 2H2O This is the balanced equation.

(3) V2O5 + CaS -----> CaO + V2S5

V is already balanced. To balance S, we need to multiply CaS by 5,

V2O5 + 5CaS -----> CaO + V2S5

Now to balance Ca we need to multiply CaO by 5

1V2O5 + 5CaS -----> 5CaO + 1V2S5   this is the balanced equation.

(4) S8 + O2 -----> SO2

for balancing S, we need to multiply SO2 by 8.

S8 + O2 -----> 8SO2

for balancing O we need to multiply O2 by 8.

1S8 + 8O2 -----> 8SO2 this is the balanced equation.

(5) H2O2  ------> O2 + H2O

hydrogen is already balanced but oxygen is not. left side has two oxygen and right side has three oxygen. To make it balance we could multiply O2 by 1/2.

H2O2  ------> 1/2O2 + H2O

since 1/2 is not a whole number coefficient, so to make it a whole number we will multiply the complete equation by 2.

2H2O2  ------> 1O2 + 2H2O   This is the balanced equation.

(6) Al2O3 + Fe -----> Fe3O4  + Al

for Balancing Al we need to multiply Al by 2

Al2O3 + Fe -----> Fe3O4  + 2A

For balancing Fe we need to multiply Fe by 3.

Al2O3 + 3Fe -----> Fe3O4  + 2Al

for balancing O we need to multiply left Al2O3 by 4 and Fe3O4 by 3.

4Al2O3 + 3Fe -----> 3Fe3O4  +2Al

we need to balance Fe and Al again. for balancing Fe we need to multiply 3Fe by 3 and 2Al by 4.

4Al2O3 + 9Fe -----> 3Fe3O4  +8Al This is the balanced equation.

(7) S + HNO3 -----> H2SO4 + NO2 + H2O

S is already balanced. for balancing H we need to multiply HNO3 by 4.

S + 4HNO3 -----> H2SO4 + NO2 + H2O

now for balancing N we need to multiply NO2 by 4.

S + 4HNO3 -----> H2SO4 + 4NO2 + H2O

we have 12 oxygen on left side and 13 oxygen on right side. Here it is not easy to balance oxygen using these coefficients so let's try HNO3 with 6.

1S + 6HNO3 -----> 1H2SO4 + 6NO2 + 2H2O This is the balanced equation.

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