Consider a galvanic cell based on the following line notation at 299 K: Cr|Cr 3+
ID: 520172 • Letter: C
Question
Consider a galvanic cell based on the following line notation at 299 K:
Cr|Cr3+||Cd2+|Cd
where the standard cell potential is 0.33 V. What will the following changes do to the potential of the cell?
increase potential decrease potential no change in potential Add water to the anode portion of the cell
increase potential decrease potential no change in potential Decrease the mass of the Cd
increase potential decrease potential no change in potential Add equal amounts of water to both the anode and cathode portions of the cell
Explanation / Answer
the reaction taking place is:
Cr (s) + Cd2+ (aq) —> Cr3+ (aq) + Cd (s)
formula for calculating E cell is
E = Eo - (0.0592/n) log {[Cr3+]^1/[Cd2+]^1}
Add water to the anode portion of the cell
This means adding water to Cr cell
This will decrease the concentration of Cr3+
So, E will increase as per above equation
Answer: increase
Decrease the mass of the Cd
mass do not appear in the equation of E
So, mass will not effect E
Answer: No change
Add equal amounts of water to both the anode and cathode portions of the cell
We are changing the concentration of both by same amount
So, E will not change
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