What mass of manganese(II) chloride must react with sulfuric acid to release 49.

Question

What mass of manganese(II) chloride must react with sulfuric acid to release 49.0 mL of hydrogen chloride gas at STP? MnCl2(s)+H2SO4(aq)MnSO4(aq)+2HCl(g)
Express your answer with the appropriate units. What mass of manganese(II) chloride must react with sulfuric acid to release 49.0 mL of hydrogen chloride gas at STP? MnCl2(s)+H2SO4(aq)MnSO4(aq)+2HCl(g)
Express your answer with the appropriate units. What mass of manganese(II) chloride must react with sulfuric acid to release 49.0 mL of hydrogen chloride gas at STP? MnCl2(s)+H2SO4(aq)MnSO4(aq)+2HCl(g)
Express your answer with the appropriate units.

Explanation / Answer

From given balanced chemical equation we can say that

1 mole MnCl2 produce 2 mole HCl

2 mole HCl i.e 44.8 L HCl is produced by 1 mole MnCl2 i.e 126g MnCl2

So 49 ml HCl would be produced by:-0.137g MnCl2

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