The quantity of antimony in an ore can be determined by an oxidation-reduction t

Question

The quantity of antimony in an ore can be determined by an oxidation-reduction titration with an oxidizing agent. The ore is dissolved in hot, concentrated acid and passed over a reducing agent so that all the antimony is in the form Sb^3+(aq). The Sb^3+(aq) is completely oxidized by an aqueous solution of BrO_3^-(aq). Complete and balance the equation for this reaction in acidic solution. BrO_3^- + Sb^3+ rightarrow Br^- + Sb^5+ + 3H_2 O Br" + Sb5' +3H20 If you need to clear your work and reset the equation, click the button that looks like two red arrows.

Explanation / Answer

if acidic:

BrO3- = Br-

Sb+3 = Sb+5

balance O

BrO3- = Br- + 3H2O

Sb+3 = Sb+5

balance H+

6H+ + BrO3- = Br- + 3H2O

Sb+3 = Sb+5

balance charges

6e- + 6H+ + BrO3- = Br- + 3H2O

Sb+3 = Sb+5 + 2e-

balance e-

6e- + 6H+ + BrO3- = Br- + 3H2O

3Sb+3 = 3Sb+5 + 6e-

add all

3Sb+3 + 6e- + 6H+ + BrO3- = Br- + 3H2O + 3Sb+5 + 6e-

cancel common terms

3Sb+3 + 6H+ + BrO3- = Br- + 3H2O + 3Sb+5

this is now acidic balanced

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.