Lab 10: Determinason of Man by Reaction with Permanganate A Redox Titration. eue
ID: 518220 • Letter: L
Question
Lab 10: Determinason of Man by Reaction with Permanganate A Redox Titration. euen Name Advance Study Assignment: Determination of Iron by Reaction with Permanganate-A Redox Titration 1, write the balanced net ionic equation for the reaction between Mnoi ion and Fe?" ion in acid solution. 2. How many moles of Fed' ion can be oxidized by 1.3 x lor moles Mno, ion in the reaction in Question 1? moles 3. A solid sample containing some Fea" ion weighs 1.264 g. It requires 38.67 ml. o02487 M KMno, no titrate the Fe in the dissolved sample to a pink end point. a. How many moles of Mno ion are required? How many moles of Fe2. are there in the sample? c. How many grams of iron are there in the sample? d. What is the mass percent o i what is the mass percent of Fe in ironan ammonium sulfate hexahydrate, FedNH..soa, 6 Ho? 157Explanation / Answer
In the given reaction, iron is oxidised and the manganese ions are reduced.
OXIDATION: Fe^2+(aq) Fe^3+(aq) + e
REDUCTION: MnO4^-(aq) + 8H^+(aq) + 5e Mn^2+(aq) + 4H2O(l)
To get the net ionic equation:
Add both the oxidation and the reduction reaction as follows:
5Fe^2+(aq) + MnO4^-(aq) + 8H^+(aq) 5Fe^3+(aq) + Mn^2+(aq) + 4H2O(l)
From equation, n(Fe^2+) / n(MnO4^-) = 5 / 1
So,
b)
So, n(Fe^2+) = (5 / 1) * 1.3 * 10 ² = 6.5 * 10 ² mol
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