A current of 4.11 A is passed through a Cu(NO3)2 solution. How long (in hours) w

Question

A current of 4.11 A is passed through a Cu(NO3)2 solution. How long (in hours) would this current have to be applied to plate out 5.10 g of copper?

Question 28 of 36 Incorrect X Map A Sapling Learning A current of 4.11 A is passed through a Cu(NO3)2 solution How long (in hours) would this current have to be applied to plate out 5-10 g of copper? Number 1.58 There is a hint available! View the hint by clicking on the bottom divider bar. Click on the divider bar again to hide the hint. O Previous ® Give up & View solution Check Answer 0 Next Exit 8 Hint

Explanation / Answer

Cu+2  + 2e-  ---------> Cu

63.546 g Cu require 2 x 96487 Columbs charge.

5.10 g Cu require 5.10 x 2 x 964897 / 63.546 = 15487.5 C

15487.5 C charge required.

charge = current x time in s

15487.5 = 4.11 x t

t = 3768.25 s = 62.80 min = 1.05 h

answer = t = 1.05 h

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