The average distance between the Earth and the Moon is 240,000 miles. Express th

Question

The average distance between the Earth and the Moon is 240,000 miles. Express this distance in kilometers, (1 mi = 1609m) A) 6.1 times 10^5 km B) 5.3 times 10^5 km C) 3.9 times 10^5 km D) 1.5 times 10^5km E) 9.4 times 10^4 km If you have a graduated cylinder, containing 15.5 mL and this volume changes to 95.2 mL after a metal with a mass of 7.95 g is dropped into the graduated cylinder then what is the density of this metal? A) 0.0835 g/mL B) 0.513 g/mL C) 0.0718 g/mL D) 10.0 g/mL E) 9.97 times 10^-2 g/mL Bromine is the only nonmetal that is a liquid at room temperature. Consider the isotope bromine-81. Select the combination which lists the correct atomic number, neutron number, and mass number, respectively.^81_35 Br A) 35, 46, 81 B) 35, 81, 46 C) 81, 46, 35 D) 46, 81, 35 E)35, 81, 116 What is the mass percent of oxygen in barium perchlorate? A) 4.7% B) 8.5% C) 23.4% D)38% E)18.7% Balance the following equation for the combustion of benzene: C_6 H_6(l) + O_2 rightarrow H_2O(g) + CO_2 (g) A) C_6 H_6 (l) + 9O_2 (g) rightarrow 3H_2O(g) + 6CO_2 (g) B) C_6H_6 (l) + 9O_2(g) rightarrow 6H_2O(g) + 6CO_2 (g) C) 2C_6H_6 (l) + 15 O_2 (g) rightarrow 6H_2O(g) + 12 CO_2(g) D) C_6H_6 (l) + 15 O_2 (g) rightarrow 3H_2O(g) + 6CO_2(g) E) 2C_6H_6(l) + 9O_2 (g) rightarrow 6H_2O(g) + 12 CO_2 (g) What is the empirical formula for a 100 g sample containing 87.42 g of nitrogen and 12.58 g of hydrogen? A) NH B) N_2 H C) NH_2 D) NH_3 E) NH_4 Sulfur dioxide reacts with chlorine to produce thionyl chloride and dichlorine oxide. SO_2 (g) + Cl_2 (g) rightarrow SOCl_2 (g) + Cl_2 O(g) (Not balanced!!) If 0.400 mol of Cl_2 reacts with excess SO_2. how many moles of Cl_2 O are formed? A) 0.800 mol B) 0.400 mol C) 0.200 mol D) 0.100 mol E) 0.0500 mol

Explanation / Answer

1) Average distance between earth and moon is 240,000miles

Given that, 1 mile = 1609 m

thus, 240,000 mile = (240,000) x (1609) m = 386160000 m

We know that 1m= 10-3 K.M

Thus, 386160000 m = (386160000) x 10-3 K.M = 386160 KM = 3.86 x 105 nearly equals to 3.9 x 105km

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