Please show me the answer and the ditailed solution of this question. Styrene(C8

Question

Please show me the answer and the ditailed solution of this question.

Styrene(C8H8) and Ethylbenzene(C8H10) are two organic liquids wich form a nearly ideal solution.

Consider a styrene/ethylbenzene solution that is 38% styrene and 62% ehtylbenzene by mass.

a) Calculate the total vapour pressure above this solution at 90.0 (assume ideal behaviour ) given the vapour pressures of pure styrene and ethylbenzene at this temperature are 134mmHg and 182 mm Hg respectively

b) Calculate the mole fractions of styrene and ethylbenzen in the vapour above this liquid at 90

c) Consider removing a sample of the vapour from part b and condensing it into a liquid in a saparete vessel. Caluculate the mole fraction of ethylbenzene in the vapour above this liquid at 90

Explanation / Answer

From Raoults’ law, y1P=x1P1sat and y2P=x2P2sat, where y1,y2 are mole fraction of styrene and ethyl benzene in the vapor phase, x1, x2 are mole fractions in the liquid phase, P1sat and P2 sat are saturation vapor pressures.

Addition of two equations give P=x1P1sat+x2P2sat= 0.38*134+0.62*182=164 mm Hg.

Hence y1= x1P1sat/P= 0.38*134/164 =0.31 and y2=0.62*182/164=0.69.

When the vapor is condensed, liquid composition of ethyl benzene will be 0.69 and that of styrene is 0.31. P= 0.69*182+0.31*134 = 167 mm Hg

Hence vapor composition, y2= 0.69*182/167 = 0.75

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