The correct cell notation for the following reaction: Ni(s) + Cd^2+(aq) rightarr

Question

The correct cell notation for the following reaction: Ni(s) + Cd^2+(aq) rightarrow Cd(s) + Ni^2+(aq) is Ni(s) Nr^2+(aq) || UCd^2+(aq) | Cd (s), because: a) Cadmium is oxidized, the nickel ion is reduced and the oxidation step is always written on the left side of the cell notation. b). Nickel is oxidized, the cadmium ion is reduced and the oxidation step is always written on the left side of the cell notation. c). Nickel is oxidized, the cadmium ion is reduced and the oxidation step is always written on the right side of the cell notation. d) Nickel is reduced, the cadmium ion is oxidized and the oxidation step is always written on the right side of the cell notation.

Explanation / Answer

To remember the writing rule of any cell,

ust memorise this phrase

Anode-oxidation-left-negtive

it means anode undergo oxidation and is written at left and its charge notation is negative.

here,

Ni-------------->Ni2+ + 2e-

Cd2+ + 2e-------------> Cd

means Nickel undergo oxidation and Cadmium undergo reduction.

so answer B is correct

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