1.) 4HCl(g)+O2(g)====>2Cl2(g)+2H2O(g) Calculate the number of grams of Cl2 forme

ID: 515927 • Letter: 1

Question

1.) 4HCl(g)+O2(g)====>2Cl2(g)+2H2O(g)

Calculate the number of grams of Cl2 formed when 0.470 mol HCl react with O2.

2.) 2KClO3====>2KCl+3O2

If this reaction produced 97.2 g of KCl, how much O2 was produced (in grams)?

3.) Gaseous hydrogen and oxygen can be prepared in the laboratory from the decomposition of gaseous water. The equation for the reaction is

2H2O(g)====>2H2(g)+O2(g)

Calculate how many grams of O2(g) can be produced from 85.6 grams of H2O(g).

4.) 2H2O2(l)+N2H4(l)=====>4H2O(g)N2(g)

determine how many grams of N2 are produced from the reaction of 8.85 g of H2O2 and 6.82 g of N2H4.

5.)2NaI(aq)+Cl2(g)===>I2(s)+2NaCl(aq)

How many grams of sodium iodide, NaI, must be used to produce 67.3 g of iodine, I2?

1.) 4HCl(g)+O2(g)---------------------> 2Cl2(g)+2H2O(g)

4 2

4 mol HCl gives ------------------> 2 mol Cl2

0.470 mol HCl gives --------------> 2 x 0.470 / 4 = 0.235

moles of Cl2 = 0.235

mass of Cl2 = 0.235 x 71 = 16.7 g

mass of Cl2 produced = 16.7 g

2.) 2KClO----------------------->2KCl + 3O2

149.1g 96 g

149.1 g KCl ----------------------> 96 g O2

97.2 g KCl ----------------------> 96 x 97.2 / 149.1 = 62.6 g

mass of O2 produced =62.6 g

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