rt Format Arrange View Share Window Help g Untitled 2 v 150% Edited Insert Table

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rt Format Arrange View Share Window Help g Untitled 2 v 150% Edited Insert Table Chart Text Shape Media Comment 1 Data and Calculations Tablet 1 Milligrams of active ingredient 1000 mg Mass of tablet beaker 100.37 g 6 Mass of empty beaker 98.15 g 7 Net of mass tablet 2.21 g 8 Molarity of HCL solution 3 M Volume of HCL added to tablet 5 mL 10 Molarity of NaoH titrant 6 M 11 Volume of NaoH Titrant Final buret reading 43.47 mL Initial buret reading 12 39.49 mL 13 Net volume of NaOH 3.98 mL Millimoles of HCL solution added to tablet ,5 Millimoles of NaOH solution required to neutralize the excess HCL 16 Millimoles of HCL neutralized by the antacid tablet 17 Calculated mass, mcacl, of active ingredient 18 Milligrams of active ingredient, mfg percentage relative difference moact mmig Mass of inert binder in tablet Mass of inert binder

Explanation / Answer

Tablet analysis

Mass of active ingredient = 1000 mg (0.1 g)

mass of tablet = 2.22 g

Total moles of HCl added = 3 M x 5 ml = 15 mmol

moles NaOH needed = 6 M x 3.98 ml = 23.88 mmol

Here, moles of NaOH used for neutralization is much higher than the total moles of HCl added intially to the tablet

Thus, the values are incorrect and needs be fixed

Once correct values are added

moles of HCl reacted = Total moles of HCl added - moles of NaOH used

moles of active ingredient = moles of HCl reacted

Given the formula of the acitive ingreadient and molar mass

mass of active ingredient in tablet = moles of active ingredient x molar mass of ingredient

% mass of inert material = (Total mass of tablet - mass of active ingredient) x 100/total mass of tablet

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