a 0.85 g sample of unknown gas has a volume of A 0.85 g sample of unknown gas ha

Question

a 0.85 g sample of unknown gas has a volume of A 0.85 g sample of unknown gas has a volume of 350 mL at 29.1 in. of Hg and a temperature of 100.0 degree C. Calculate the molar mass of the gas. A student adds 10.00 mL of 0.240 M of oxalic acid to 10.00 mL of distilled water. To this solution the student adds 4.00 mL of 0.060 M potassium permanganate. The total volume of the mixture is 24.0 mL. The elapsed time for the reaction is 18s. a) Calculate initial concentration of oxalic acid in the reaction mixture. b) Calculate the initial concentration of potassium permanganate in the reaction mixture. c) Calculate the initial rate of the reaction.

Explanation / Answer

Data is not clearly visible in image. But still i am considering the values and giving the answer.

NOW APPLY IDEAL GAS EQUATION.

i.e. PV = nRT Where n = number of moles of gas

  n = given mass of gas/ molar mass of gas = W/M

Put tHe vale of " n" in ideal gas equation and get the relation between molar mass of gas and other parameters.

PV = (W/M)*RT

M = WRT/PV. Where R = gas constant and its vale is 0.0821 L atm mol-1K-1.

M = [ 0.85*0.0821*373]/0.38*0.350

M = 195.7 g

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