sapling learning.com Clemson University CH 1020 Spring1... Consider a generic re

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sapling learning.com Clemson University CH 1020 Spring1... Consider a generic redox reaction? I Ya For the following electrochemical cell...? alculate the cel all for the fol ling Learning l Clemson University-CH 1020 Spring17-HWU Activities and Due Dates I HW 7 Assignment Attempts Score Weight 4/18/2017 11:55 PM CA 81.3/100 Grade book Print acalculator Periodic Table 000 Question 14 of 17 Map 000 Sapling. Learning 00 Calculate the cell potential for the following reaction as written at 25.00 c, given that [zn2 0.859 M and [Ni21 0.0150 M. Standard reduction potentials can be found here. 00 zn' (aa) Nils Zn s agl 100 Number 000 000 10 85 11 00 12 13 000 14 15 16 G Previous 8 Give Up & View solution check Answer Next Hint 17 2017 Sapling Learning, Inc. about us careers partners l privacy policy terms of use Contact us help Chemistry question I Chegg.com Resources OAssignment Information Available From: 4/7/2017 12: 4/18/2017 1 Due Date: Points Possible Grade Category: Graded Description: Policies: Homework You can check your answers. You can view solutions when you up on any question. You can keep trying to answer e you get it right or give up. You lose 5% of the points availab in your question for each incorre answer. O eTextbook O Help With This Topic Web Help & Videos O Technical Support and Bug

Explanation / Answer

Given

Zn (s) + Ni2+ (aq) -----> Ni (s) + Zn2+  (aq)

half cell potential

oxidation Zn -----> Zn2+ + 2 e-   Eo = - 0.762 V

reduction Ni2+ + 2 e-   -----> Ni Eo = - 0.28 V

Eo cell = Eo reduction - Eo oxidation = - 0.28 V - ( - 0.762 V) = 0.482 V

Ecell = Eocell - (RT/nF) ln Q =  Eocell - (0.0257/n) ln Q =  Eocell - (0.0592/n) log Q

            Ecell = cell potential at non-standard state conditions
            Eocell = standard state cell potential = 0.482 V
            R = constant (8.31 J/mole K)
            T = absolute temperature (Kelvin scale)
            F = Faraday's constant (96,485 C/mole e-)
            n = number of moles of electrons transferred in the balanced equation for the reaction occurring
                  in the cell
            Q = reaction quotient for the reaction.

Q = Zn2+ / Ni2+ = 0.859 M / 0.0150 M = 57.2666

no. of electrons transferred n = 2

sub values

Ecell = = 0.482 - (0.0592 / 2) log (57.2666) = 0.43 V Answer

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