The following reaction occurs in acidic solution. Identify the correct half-reac
ID: 513877 • Letter: T
Question
The following reaction occurs in acidic solution. Identify the correct half-reaction that applies to the reducing agent. Cr_2 O_7^2- (aq) + C_2 H_5 OH (aq) rightarrow C_2 H_4 O (aq) + Cr^3+ (aq) (a) C_2 H_5 OH rightarrow C_2 H_4 O + 2H^+ + 2e^- (b) Cr_2 O_7^2- + 3e^- rightarrow Cr^3+ + 7 H_2 O (c) C_2 H_5 OH + 2e^- + 2 H^+ rightarrow C_2 H_4 O + H_2 O (d) 14 H^+ + Cr_2 O_7^2- rightarrow 2 Cr^3+ + 7 H_2 O + 8e^- (e) 14H^+ + Cr_2 O_7^2- + 6e^- rightarrow 2 Cr^3+ + 7 H_2 O Consider the reaction, Sn + Au^3+ rightarrow Sn^2+ + Au. Which of the following is NOT correct? If more than one is NOT correct, respond E. (a) The oxidation half-reaction is Sn rightarrow Sn^2+ + 2e^-. (b) The reduction half-reaction is Au^3+ + 3e^- rightarrow Au. (c) Au^3+ is the oxidizing agent. (d) The equation is balanced as written. (e) More than one statement is NOT correct. A voltaic cell is constructed based on the oxidation of zinc metal and the reduction of silver (I) ions. Solutions of 1.00 M silver nitrate and zinc nitrate also were used. The anode is on the left; the cathode, on the right. Locate the silver electrode on the diagram.Explanation / Answer
32 answer : option E
Cr2O72– + C2H5OH .--à Cr 3+ + CO2
Cr2O72– .-----.> 2 Cr 3+
Cr2O72– . -à 2 Cr 3+ + 7 H2O
14 H + + Cr2O72– -à. 2 Cr 3+ + 7 H2O
6 e – + 14 H+ + Cr2O72– -à. 2 Cr 3+ + 7 H2O
C2H5OH-à . 2 CO2 O
3 H2O + C2H5OH . -à 2 CO2 + H
3 H2O + C2H5OH . -à 2 CO2 + 12 H +
3 H2O + C2H5OH -----à 2 CO2 + 12 H+ + 12 e –
QUESTION 33
CONSIDER the reaction sn + au3+--àsn2+ + au which of the following is Not correct
Answer : E
The oxidation half reaction is sn------àsn2+ +2e----------- Not correct ---
QUESTION 34
…..ANODE IS ON THE LEFT , THE CATHODE ON THE RIGHT ………………..
ANSWER :OPTION B
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