At room temperature, the observed value of mu for [Co (H_2 O)_6] Br_3 is 4.75 mu

Question

At room temperature, the observed value of mu for [Co (H_2 O)_6] Br_3 is 4.75 mu_s. Is the complex high- or low*spin? Given: mu_df = (n(n + 2))^1/2; where n is the number of unpaired electrons. Solution: the overall formation constants for the action of Fe (OH_2)_6^2* with bipyridyl (a bidendate nitrogen chelate) are: beta_1 = 1.6 times 10^4 M^-1; beta_2 = 8.0 times 10^7 M^-2; beta_3 = 1.6 times 10^17 M^-3 a) How is the stability constant beta_3 related to K_1, K_2 and K_3 by Solution: b) The expected trend for the successive K values for this kind of reactions is Solution:

Explanation / Answer

2) magnetic moment 4.75 BM confirm that there are 4 unpaired electrons. Co^3+ has six electrons in 3d subshell, so get 4 unpaired electrons complex should be high spin.

3)a) B3= K1*K2*K3

b) K1> K2> K3

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