The quantity of antimony in a sample can be determined by an oxidation-reduction

Question

The quantity of antimony in a sample can be determined by an oxidation-reduction titration with an oxidizing agent. A 7.31-g sample of stibnite, an ore of antimony, is dissolved in hot, concentrated HCI (aq) and passed over a reducing agent so that all the antimony is in the form 3+ The Sb3+(aq) is completely oxidized by 29.6 mL of a 0.140 M aqueous solution of KBro3(aq). The unbalanced equation for the reaction is Bro, (aq) sbs" (aq) Br (aq) +sbs (aq) (unbalanced) Calculate the amount of antimony in the sample and its percentage in the ore Number Number

Explanation / Answer

The balance equation of the reaction is-

BrO3{-} + 3 Sb{3+} + 6 H{+} Br{-} + 3 Sb{5+} + 3 H2O

(0.0296 L) x (0.140 mol/L KBrO3) x (3 mol Sb / 1 mol KBrO) x (121.76 g Sb/mol) = 1.51 g Sb

(1.51 g) / (7.31 g) = 0.206 = 20.6% Sb

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