1. Below is a consensus promoter sequence in E. coli 5’ - TTGCACAT 15 to 17 bp T

Question

1.Below is a consensus promoter sequence in E. coli

                                                       5’ - TTGCACAT 15 to 17 bp TATAAT – 3’

Write the complementary strand of DNA below the original strand.

In which direction would transcription from this promoter proceed?

Write the sequence (both strands) of the consensus promoter that would cause transcription to proceed in the opposite direction. Indicate the 5’ and 3’ end of each molecule.

write the amino acid sequence of the protein that would be produced by this gene.

Explanation / Answer

The complementary strand of DNA below the original strand is given as:

5’ - TTGCACAT 15 to 17 bp TATAAT – 3’

3' - AACGTGTA 15 to 17 bp ATATTA - 5'

The transcription from this promoter will proceed from 5' to 3' direction.

The sequence that will cause transcription to occur in the opposite direction:

3' - AACGTGTA 15 to 17 bp ATATTA - 5'

5’ - TTGCACAT 15 to 17 bp TATAAT – 3’

The amino acid that will be produced will be based on the mRNA sequence:

5’ - TTGCACAT 15 to 17 bp TATAAT – 3’

3' - AACGTGTA 15 to 17 bp ATATTA - 5'

mRNA- 5' - UUGCACAU 15 to 17 bp UAUAAU- 3'

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