Hydrazine reacts with O 2 to form water and N 2 . N 2 H 4 () + O 2 (g) 2H 2 O()

Question

Hydrazine reacts with O2 to form water and N2.

N2H4() + O2(g) 2H2O() + N2(g)

Hr° = -622.29 kJ/mol-rxn

rS° = 4.87 J/Kmol-rxn

rG° = -623.75 kJ/mol-rxn

Because this is an exothermic reaction, energy is evolved as heat. What temperature change is expected in a heating system containing L of water if 1.00 mole of N2H4() reacts?

Assume no energy is lost to the surroundings.

Hydrazine reacts with O2 to form water and N2.

N2H4() + O2(g) 2H2O() + N2(g)

Hr° = -622.29 kJ/mol-rxn

rS° = 4.87 J/Kmol-rxn

rG° = -623.75 kJ/mol-rxn

Because this is an exothermic reaction, energy is evolved as heat. What temperature change is expected in a heating system containing L of water if 1.00 mole of N2H4() reacts?

Assume no energy is lost to the surroundings.

Explanation / Answer

We know

rG° = Hr° - T*rS°

-623.75 = -622.29 -T*(0.00487)

T = 300 K

So this reaction is happening at 300 K

If the intial tempeature is say 25 deg C or 298 K then temperature difference of 2 K expected.

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