please need help woth this volume of olarity of Submit Hints My Answers Gave Up
ID: 511877 • Letter: P
Question
please need help woth this
Explanation / Answer
Ans:
2KMnO4 (aq) + H2O2 (aq) +3H2SO4 (aq) -----> 3O2 (g) + 2MnSO4 (aq) + K2SO4 (aq) + 4H2O (l)
Number of moles = Molarity * Liters of solution
So, 1.68 * 0.0173 = 0.029064 mole of KMnO4
2 moles of KMnO4 reacts with 1 mole of H2O2 (from the balanced chemical equation),
So, 0.029064 mole of KMnO4 reacts with 1/2 x 0.029064 mole of H2O2
Mass of H2O2 = (1/2 x 0.029064 mole of H2O2 ) x (mass of 1 mole of H2O2 )
= 0.014532 moles x 34.02 g = 0.4940 g H2O2
So, mass of H2O2 required is 0.4940 g
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