vinegar number 2, Mass of flask 3. Mass of nask 5.00 mL of vinegar 4. Mass of 5.

Question

vinegar number 2, Mass of flask 3. Mass of nask 5.00 mL of vinegar 4. Mass of 5.00 mL of vinegar 5. Density of vine 6- Molarity of sodium hydroxide solution Titrations flask 1 7. Final buret reading 8, Initial buret reading 48.9 9. Volume of NaOH soln. Ln 10. Moles of NaOH 11. Moles of acetic acid 12. Molarity of acetic acid. 13. Average molarity of acetic acid in vinegar 14. Deviation of each molarity from average 15 16. Mass percent of acetic acid in vinegar (show calculations below) o 2015 Cengage Leaming flask 2 49303 9.242 mL. l.18 M

Explanation / Answer

Q13

Average molarity = (M1+M2+M3) / 3 = (1.38+1.12 + 1.18)/3 = 1.2266

Q14

Deviation -->

a)

(1.38-1.2266)/1.2266 = 0.1250

b)

(1.12-1.2266)/1.2266 = -0.08690

c)

(1.18-1.2266)/1.2266 = -0.0379

Q15

Avg. Deviation

Avg = sqrt((0.1250^2 + (-0.08690)^2 + (-0.0379^2)) = 0.1474455

Q16.

Mass % of acid --> M =O 1.38 M

assume a basis of 1 Liter solution

1.38 mol are acetic acid

mass acetic = mol*MW = 1.38*60 = 82.8 g of acetic acid

total mass solution = 1000 g

% mass = 82.8 / 1000 * 100 = 8.28% approx

Related Questions

Navigate

• Browse (All)
• Browse V
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.