To dilute 1.00 L of a 0.600 A/to 0.100 M, the final volume must be a. 60 L. b. 0

ID: 511283 • Letter: T

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To dilute 1.00 L of a 0.600 A/to 0.100 M, the final volume must be a. 60 L. b. 0.7 L. e. 1/6 the original volume. d. More information is needed to answer this question. e. 6 times the original volume. Which of the following metals will reduce Ni^2+ in aqueous solution to Ni(s)]? a) Li b) Au c) Pt d) none of the above c) all of the above A 2.00-L glass soda bottle filled only with air is tightly capped at 25 degree C and 728.0 mmHg- If the bottle is placed in water at 65 degree C. what is the pressure in the bottle? a. 280 mmHg b. 826 mmHg c. 1890 mmHg d. 642 mmHg e. 324 mmHg what is the pressure of a 34.8-1. gas sample containing 7.45 mol of gas at 19.9 degree C? a. 2.66 times 10^21 mm Hg b. 6.77 times 10^-3 mmHg c. 514 mmHg Hg b. 6.77 times 10^-2 mmHg c. 5.14 mmHg d. 3.91 times 10^2 mmHg e. 1.48 times 10^2 mmHg The volume of a sample of gas measured at 35.0 degree C and 1.00 atm pressure is 2.00 L. What must the final temperature be in order for the gas to have a final volume of 3.00 L at 1.00 atm pressure? a. 189.0 degree C b. 52.5 degree C c. -220.5 degree C d. 23.3 degree C e. -67.7 degree C How many moles of gas are in a gas sample occupying 1.40 L at 553 mmHg and 294 K? a. 32.1 mol b. 0.0422 mol c. 23.7 mol d. 0.00346 mol e. 2.63 mol The density of ethane, C_2H_6 (30.1 g/mol), at 25 degree C and 1.13 atm pressure is a. 1.39 g/L b. 16.6 g/L c. 1344. g/L d/0.719 g/L e. 0.136 g?L

Explanation / Answer

6) moles of solute befre dilution = after dilution

1L x 0.6 M = V x 0.1 M

thus V = 6 L

OPTION e

7) the elements above the metal NI can replace it from its salt solution .

Among the given ones , onlu Li is the one above Ni in electrochemical series.

thus OPTION a

8) As volume of container remains constant , we use the relation

P1V1 /T1 = P2V2 /T2

728mm x 2 L /298 K = P2 x 1L /338K

thus P2 = 825.71 mm

OPTION b

9) PV = nRT

P = 7.45mol x 0.0821L.atm/mol.K x 292.9K /34.8L

= 5.148 atm

We know 1atm = 760mm-Hg

thus P = 5.148x760

= 3.91 x 103mm-Hg

OPTION d

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To dilute 1.00 L of a 0.600 M to 0.100 M, the final volume must be A. 1/6 the or

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To dilute 1.00 L of a 0.600 A/to 0.100 M, the final volume must be a. 60 L. b. 0

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