Note: I have no additional info to provide... We literally just added HCl to the

Question

Note: I have no additional info to provide...
We literally just added HCl to the following reaction then did titration using NaOH and phenolphthalein as an indicator (3drops)...
Each bottle contained a different amount of the reactants of this equation... they all had the same amount of HCl added and obviously a different amount of NaOH added to reach the equivalence point. Hi, Can you please help me answer this question? I am having trouble figuring it out... Can you provide explanations as well? Et.Ac H2O EtOH HAc Would the results of this experiment (see below) (My Keq values 1) 1.55*10A-1 2) 1.57*10 -1 3) 1.96* 10A-1 have been affected if you had forgotten to add the HCl to the reaction bottles? Why or why not?

Explanation / Answer

Ans. EtAc + H2O -----H+---------> EtOH + Ac

H+ (from HCl) acts as the catalyst in above reaction.   

As you know, a catalyst is a chemical species that increase the rate of reaction without getting consumed up during the reaction. Presence of lesser amount of catalyst (HCl) or its absence from the reaction mixture lowers the rate of reaction.

It is noteworthy that a catalyst increases the rate of reaction but does not affect the equilibrium constant. However, in absence of catalyst, the reaction time to achieve the equilibrium is prolonged, i.e. you need more that to achieve the equilibrium when catalyst is not used.

So, to check whether absence of HCl affects your reaction or not, you should compare the rate of reaction (but NOT Keq) of the uncatalyzed reaction with that of catalyzed reaction. Or, alternatively compare the time taken for attaining equilibrium for an uncatalyzed reaction with that of catalyzed reaction.

Your Keq values are nearly same as the theoretical value.

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