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Please help me finding out and let me know gow it\'s done, I appreciate it! are

ID: 510941 • Letter: P

Question


Please help me finding out and let me know gow it's done, I appreciate it! are floating in the water along with the iron ions. The chloride does nothing during the actual however, so why bother having them in the reaction equation? Their presence makes it more difficult to keep track of the electrons that are moving around. The reaction you will be using in the titration today will be one of the following as determined by your instructor. You should be able to balance the appropriate reaction. MnO Fe (Procedure B) Mn2. 3+ Fe 4 (aq) (aq) (aq) MnO H,O Mn2. (Procedure O. C 4 (aq) (aq) 2(g) (Procedure D) I, SO 2- I- S.O CHEMICALS Molar/Formula Mass, Physical Safety Concerns Possible Use Substance Characteristics Conc 00 M Dark purple solution Skin staining Titrant KMnO Fe(NO),ad, 0.01 M to o 1 M Pale green solution Heavy metal Analyte Ho 0.01 M to 0.1 M Colorless solution None Analyte Colorless solution Caustic Analyte NaCloosa) 0.01 M to 0.1 M Colorless solution None Titrant Na 2 2 3 (aq) 0.1 M Yellow solution Skin staining indicator 0.2 M opaque suspension None Indicator Starchaam 19% m/v

Explanation / Answer

B. in this reaction MnO4 ^-1 act as a oxidising agent so it will oxidised the Fe2+ into Fe3+ and self get reduced therefore in the solution of Fe(NO3)2 having green colored solution changes to

the color change during the redox reaction is as follows: Blue color .

C. In this case also MnO4- or inNY Case Mno4- always behaves as a oxidising agent. so during dilution color of KMnO4 fades and give light purple color.

D. In this case iodide ion is behaves as a oxidising agent and as the reaction shows it is oxidising the ClO- to Cl-

and intially this solution is colorless after adding Potasssium iodide it gives Blue black apperaence will come dure to starch is present .

and after that liberated I2 will treated with sodiumthiosulphite via titration also give the Blue Black appearence .

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