C Chegg Study l Guided S x C Chegg Study Guided Lyndon State College So X www.sa

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C Chegg Study l Guided S x C Chegg Study Guided Lyndon State College So X www.saplinglearning.com/ibiscms/mod/ibis/view.php?id 3173739 Apps HP Connected D estudent.hu son O User Dashboard Apple 7 Disney EESPN Y Yahoo! C Chegg study I Guid D Mobile Ei My Husson 4/17/2017 11:00 PM o/100 Gradebook Attempts Score nt Calculator Periodic Table Question 22 of 33 Map General Chemistry 4th Edition University Science Books presented by Saping Leaming Suppose that you place exactly 100 bacteria into a flask containing nutrients for the bacteria and that you find the following data at 37 C t (min) Number of bacteria 6,0 200 32.0 400 48,0 800 64.0 600 How many bacteria will be present after 112 min? What is the order of the rate of production of the bacteria? Number zero order bacteria O first order O second order What is the rate constant for the process? units Select answer min Mr 1. min" M rnin O Previous Give Up & View Solution Check Answer Next Exit c 20 2017 Sapling Learning, Inc. careers partners about us privacy policy help terms of use ontact US Other bookmarks o Assignment Information Available From: 3/27/2017 10:0 Due Date: 4/17/2017 Points Possible 00 Grade Category: Graded Description Policies: You can check your answers. You can view solutions when you up on any question. You can keep trying to answer each you get it right or give up You lose 59% of the points available in your question for each incorrect O eTextbook O Help With This Topic O Web Help & Videos O Technical Support and Bug Repo

Explanation / Answer

First order, since bacteria double every 16 minutes. This would be a straight line on a graph.

12800 bacteria will be present after 112 min. [ just double after each 16 minute ,at 80 min- 3200 ,96 min -6400 and finally at 112 min --12800]

Use first order integrated rate law
ln[A]t = –k(t) + ln[A]o
=> ln[200] = –k(16) + ln[100]
=> 5.29 = –k(16) + 4.605
=> 5.29 - 4.605 = –k(16)
=> 0.685 = –k(16)
=> –0.685 = k(16)
=> –0.685 / 16 = k
=>k = –0.043 min–1

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