The electron configuration for the carbide ion (C_2^2-) is _____. a. sigma_1s^2

Question

The electron configuration for the carbide ion (C_2^2-) is _____. a. sigma_1s^2 sigma*_1s^2 sigma_2s^2 sigma*_2s^2 pi_2p^4 b. sigma_1s^2 sigma*_1s^2 sigma_2s^2 sigma*_2s^2 pi_2p^4 sigma_2p^2 pi*_2p^2 c. sigma_1s^2 sigma*_1s^2 sigma_2s^2 sigma*_2s^2 pi_2p^2 d. sigma_1s^2 sigma*_1s^2 sigma_2s^2 sigma*_2s^2 pi_2p^4 sigma_2p^2 Which molecule (s) has a dipole moment greater than zero? What is the wavelength, in nm, of radiation which has an energy of 3.371 times 10^-19 joules per photon? a. 655.9 nm b. 152.5 nm c. 170.0 nm. d. 745.1 nm e. 589.3 nm Which sketch represents an orbital with the following set of quantum numbers: n = 3, l = 0 and m = 0 Which molecular orbital shown below arises from the destructive head-on overlap of two p atomic orbitals?

Explanation / Answer

9)

C has 6 electrons

so, C2 will have 2*6 = 12 electrons

C2 2- will have 12 + 2 = 14 electrons

In only option d, sum of the number of electrons is 14

Answer: d

10)

In a dipole moment is non 0

in b, it is 0 because both Cl group are anti to each other

In c also dipole moment is non 0

Answer: d

11)

use:

E = h*c/lambda

3.37*10^-19=(6.626*10^-34)*(3.0*10^8)/lambda

lambda = 5.893E-7 m

= 589.3 nm

Answer: e

12)

l=0 corresponds to s orbital

a is s orbital in the diagram

Answer: a

I am allowed to answer only 1 question at a time

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