In man, brown eyes (B) are dominant over blue eyes (b) and normal skin pigmentat
ID: 50912 • Letter: I
Question
In man, brown eyes (B) are dominant over blue eyes (b) and normal skin pigmentation (N) is dominant over albinism (n). A brown eyed, albino man whose mother had blue eyes and normal skin pigmentation and whose father was albino marries a blue eyed, normally pigmented woman whose father had brown eyes and was albino. (a) What is the woman's genotype? (b) What proportion of the couple's offspring would be expected to have brown eyes and normal skin pigmentation? (c) What proportion of the couple's offspring would be expected to have genotype Bbnn? (d) If the man were to marry a woman with the same genotype as his present fatherinlaw, what proportion of the offspring would be expected to have blue eyes and be albino? (e) If the woman were to marry a man with the same genotype as her present motherin-law, what proportion of the offspring would be expected to be of genotype bbNN?
Explanation / Answer
Man's Father Genotype= Bbnn (Father is carrier for blue eye gene)
Man's Mother Genotype= bbNn (carrier for albino gene)
Man's genotype=
Bbnn x bbNn
(Father) (mother)
Gametes: Bn, bn bN, bn
bN
bn
Bn
BbNn
Bbnn
bn
bbNn
bbnn
Man’s Genotype = Bbnn (Brown eye and albino)
Woman's Father Genotype = Bbnn (Brown eye and albino)
(Man) (Woman)
Gametes: Bn, bn bN, bn
bN
bn
Bn
BbNn
Bbnn
bn
bbNn
bbnn
BbNn; Brown eye and normal pigment (25%)
Bbnn Brown eye and albino (25%)
bbNn blue eye and normal pigmented (25%)
bbnn blue eye and albino (25%)
25% offspring would be expected to have brown eyes and normal skin pigmentation (BbNn)
Bbnn x Bbnn
(man) (woman with same genotype)
Gametes Bn, bn
Bn
bn
Bn
BBnn
Bbnn
bn
Bbnn
bbnn
25% offspring would be expected to have genotype bbnn (blue eye and albino)
bbNn x bbNn
(woman) (man with same mother-in-law genotype)
Gametes: bN, bn
bN
bn
bN
bbNN
bbNn
bn
bbNn
bbnn
25% offspring would be expected to have genotype bbNN
bN
bn
Bn
BbNn
Bbnn
bn
bbNn
bbnn
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