The formula of the compound: \"Sodium aquabisoxalatothiocynatoChromate (III)is:

Question

The formula of the compound: "Sodium aquabisoxalatothiocynatoChromate (III)is: a) Na[Cr(C_2O_4)_2(H_2O)(SCN)] b) Na_3[Cr(C_2O_4)2 (H_2O)(SCN)] c) Na_2 [Cr(C_2O_4)_2 (H_2O)(SCN)] Two of H_2O molecules in the complex (Cr(H_2O)_6)^+3 are replaced by two NH_3 molecules. How would the magnetism of the complex changes. a) Makes the complex more paramagnetic (b) Makes the complex more diamagnetic c) there won't be any changes in the magnetism of the complex the number of unpaired electrons () in the tetrahedral complex ion [FeCl_4] is: (remember the, CI^- is a weak field ligand: a) 1 b) 4 c) 5 d) 3 The coordination & oxidation numbers for copper in K_2[CuCl_4] respectively are: ___& ___ a) 6, 2 (b) 4, 2 c) 2, 4 d) 2, 6 The name of the complex: (Co(CN)_2(NH_3)(en)Cl]^-1 is: a) amminechlorocyanoethylenediammineCobalt(II) (b) amminechlorodicyanoethylenediammineCobaltate(II) (c) amminechlorodicyanoethylenediammineCobaltate(III) Which of the following statement is TRUE about the octahedral complexes of Ni^+ 2 a) both strong-and weak field complexes are diamagnetic b) the strong-field complex is diamagnetic and the weak-filed complex is paramagnetic c) both strong and weak complexes are paramagnetic d) The possible geometries for the ML_4 complex (M is the central metal ion, L is the ligand) are a) octahedral & tetrahedral b) octahedral & square planar c) tetrahedral & square planar

Explanation / Answer

1). H2O is neutral. thicyanato has a -1 charge, oxalate has -2 charge. Sodium has +1 charge.

Oxidation state of Cr is +3. Hence total charge of the coordination sphere is +3-4-1 =-2

Tobalance this, 2 Na must be there. Answer is c.

2). There are three unpaired electrons. Hence it is paramagnetic.

Ans is a

3). Fe3+ = 3d5

Ans is c

4). K2[CuCl4]

Coordination number = secondary valency = 2

Oxidation state = primary valency =4

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