Sapling Learning sider the nucleophilic addition reaction of 2-pentanone with ex

Question

Sapling Learning sider the nucleophilic addition reaction of 2-pentanone with excess but magnesiumbromide, made in situ by reacting 1 bromobutane with metallic magnesium, to make 4-methyl 4-octanol Mg 4-methyl-4-octanol 2-pentanone 1-bromobutane magnesium d 1.37 g/mL. d 0.81 g/mL. d 0.82 g/mL. A reaction was performed in which 0.35 mL of 2-penta none was reacted with an excess of butyl magnesiumbromide to make 0,32 g of 4-methyl-4-octanol. Calculate the theoretical yield and percent yield for this reaction. Theoretical yield Percent yield Number Number 0.47 52

Explanation / Answer

V = 0.35 mL of 2-pentanone

mass = D*V = 0.35 mL * 0.81 g /mL = 0.2835 g of 2-pentanone

moles = mass/MW = 0.2835/86.13 = 0.003291 mol of 2-pentanone

excess butyl mgbromide..

mass = 0.32 g of 4-methyl-4octanol

MW of 4-methyl-4octanol = 144.151

mol = mass/MW = 0.32/144.151 = 0.002219 moles

a)

theoretical yield:

1 mol of 2-pentanone in excess should produce 1 mol of 4-methyl-4octanol

therefore

0.003291 mol of 2-pentanone should produce 0.003291 mol of 4-methyl-4octanol

theoretical mass --> mol*MW = 0.003291 *144.151 = 0.4744 g of product

for % yield

Simply

% yield = actual / theoretical *100% = 0.32/0.4744*100 = 67.453%

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.