Have been In this exercise the amount of calcium carbonate (CaCO3 in Submitted b

Question

Have been In this exercise the amount of calcium carbonate (CaCO3 in Submitted both an antacid tablet, and an unknown sample must be 11 Answers determined and reported. Missing The chemical analysis method used will be a titration of Ca2+ with the titrant EDTA. EDTA is a ligand that will from a Write PDF file. 2+ complex ion with Ca Open Print Friendly Window. EBT is a dye that will be used to indicate the equivalence point of the titration. EBT is also a ligand, and therefore w form a different complex ion with Ca than that of EDTA. Choose a Problem Set In solution the two ligands, EDTA and EBT, compete for the Ca2+ ion. EBT has the property that when it is bonded to 2+ it Ca forms a RED complex. When it is not bonded to Ca2+ (or is free from Ca2+) it is BLUE in color. Free EBT Ca 2+ EBT As EDTA is added to the dissolved CaCO3 solution, Ca ions will break the bonds they have initially formed with the EBT dye and make new bonds with the EDTA to form a more stable complex. This process "frees up" EBT molecules in the solution.

Explanation / Answer

Answer:-

1. 6 coordinate covalent bond

2. 1 mmol Ca2+ bonds with 1 mmol EDTA

3. mmol of EDTA= molarity x volume

= 0.04820 x 25

= 1.205 mmol

4. mmol of Ca2+ = mmol of EDTA = 1.205 mmol

5. 1 mmol of CaCO3 gives 1 mmol Ca2+,

So mmol of CaCO3 = mmol of Ca2+ = 1.205 mmol.

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