if K_eq = (K_eq1)^2 and K_eq1; [P][Q]/[R] then K_eq is: A. [R]/[P][Q] B. [P]^2[Q
ID: 506169 • Letter: I
Question
if K_eq = (K_eq1)^2 and K_eq1; [P][Q]/[R] then K_eq is: A. [R]/[P][Q] B. [P]^2[Q]^2/[R] C. [R]^3/[P]^3[Q]^3 D. [P]^2[Q]^2/[R]^2 E. [R]^2/[P]^2[Q]^2 The equilibrium constant for the formation of hydrogen sulfide from hydrogen and sulfur is 0.25 at a certain temperature. H_2(g) + S(g) doubleheadarrow H_2S (g) A. The reaction favors the formation of products B. The reaction won't reach the equilibrium C. The reaction doesn't favors the formation of reactants D. The equilibrium lies to the right E. The reaction favors the formation of reactants An equilibrium that strongly favors reactants has ____ A. a value of Q >> 1. B. a value of K >> 1. C. a value of KExplanation / Answer
Solution:-
(1) If the square of Keq is done then the sqare to the other side should also be done and then the right choice would be D.
(2) Reaction favors the products if K<<1. The given value of K in the problem is 0.25 which is less than 1. So, the correct choice is A) The reaction favors the formation of products.
(3) Reaction is products favored if K>>1 and reactants favored if K<<1.
We are asked for the equilibrium that strongly favors reactants then the right choice is (C) k<<1
(4) Q ----> K <------ Q
Above arrows indicates that if Q << K then equilibrium shifts towards the products so the the equilibrium could be restabilished and if Q >> K then equilibrium shits towards reactants so the equilibrium could be restabilished.
in question it says Q has smaller value than K, it means Q <<K. So, the reaction will continue to make more products. (Choice A)
(5) In equilibrium expressions solids and liquids are not involbed it is because the change in concentrations for these is considered to be constant. So, the right choice is (C) have constant values, cs and cl.
(6) If we consider a hyothetical equation.. aA + bB -----> cC + dD
Then the rate of reaction could be written as...
rate = -(1/a) dA/dt = -(1/b) dB/dt = (1/c)dC/dt = (1/d)dD/dt
negative signs are only for the reactants as their concentrations decreases as the reaction proceeds. Also it could be noticed that the cofficients are inverted means written as 1/coefficient.
in question, the equation is given as..
3A + 5B ----> 4C + D
the rate of reaction could be written as..
rate = -(1/3)dA/dt = -(1/5)dB/dt = (1/4)dC/dt = dD/dt
from here..
rate = -(1/3)dA/dt
so, the correct choice is E.
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