or questions 30 and 31, refer to the following experi In a certain mammal, three
ID: 50603 • Letter: O
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or questions 30 and 31, refer to the following experi In a certain mammal, three genes are linked: demeanor (nd drooling (C). For demeanor (behavior), allele A is dominant and codes for angry, while a codes codes for green. For drooling, D is dominant and codes f ABC/ ABC x abc/ abc to produce the heterozygote ABC surprise this cross produced a thousand offspring! The mental analysis of the inheritance of three genes for chill, For eye color, B is dominant and codes for blue while b or drool, while d codes for no drool. You perform a cross genes are linked: demeanor (A), eve color (B), and droo emeanor (A), eve color (B), and drooling (C). For demeanor (behavior), ygote A BC/ abc You oross an F1 individual to a tester (abol abo) and to your phenotypes of those thousand offspring are given below Number Genotype observed Phenotype angry, blue, drools chill, green, no drool angry, green, no drool chill, blue, drools angry, green, drools chill, blue, no drool angry, blue, no drool chill, green, drools 428 ABC/abc 427 abc/abc 47 Abc/aboc 48 aBC/abc 22 AbC/abc 23 aBc/abc 2 ABc/abc 3 abC/aboc total 1000 30) What is the gene order of the three genes? 30) A) ABC B) CBA C) ACB D) CAB E) BAC 31) What is the recombination frequency between genes A and B? 31) -A) 0.1 B) 0.05 C) 0.20 D) 0.15 E) 0.25Explanation / Answer
30- Gene order making is so simple we can just choose the two gene which occur very frequent and two gene which occur very less. This is decided by the data we have. so first we see the two gene occur most in A B C so first we make pair of A and B, and B and C then C and A
so A and B - 428 +2 = 430 , B and C = 428 +48 = 476 and C and A = 428 +22 = 450 so we get maximum no in B and C pair and least no in A and B- so when we move B to C frequency is more A to B very less. now we see that B when pair with C and A give maximum no so B is in first place when C combine to A give minmum no so in last place so the gene order is BAC.
31 - recombination frequency between A and B (AABB * aabb)(ABC/abc are parentalso leave this phenotype) (AB, ab, aB, Ab )- calculate all the no of progeny which is produced by the genetype invoving A and B - 47+48+22+23 + 2 +3= 145
= 145 /100 = 0.145 or 0.15 so the D is correct answer
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