Under certain condition for the reaction A B, H = 19.2 kJ and S = 24 J/K. At wha

Question

Under certain condition for the reaction A B, H = 19.2 kJ and S = 24 J/K. At what temperature in K is the reaction at equilibrium?

Check the correct statements for the above reaction.

Select one or more:

a. The reaction is exothermic.

b. The reaction is endothermic.

c. The change in entropy is positive.

d. The change in entropy is negative.

e. Above the equilibrium temperature, the reaction is spontaneous to the right.

f. Above the equilibrium temperature, the reaction is spontaneous to the left.

g. Below the equilibrium temperature, the reaction is spontaneous to the right.

h. Below the equilibrium temperature, the reaction is spontaneous to the left.

Explanation / Answer

Gibbs free energy equation is ,

G = H – TS

G =0 at equilibrium,

H=change in enthalpy=19.2 KJ= 19200 J (endothermic as it is positive)

S= change in entropy= 24 J/K

0=(19200-(T x 24))

T x 24= 19200

T= 19200/24

=800 K

b. The reaction is endothermic.( H is positive )

c. The change in entropy is positive. (S=24 J/K is positive )

e. Above the equilibrium temperature, the reaction is spontaneous to the right.(For a endothermic reaction if you are adding heat,it will shift reaction to right at high temperature)

h. Below the equilibrium temperature, the reaction is spontaneous to the left. (For a endothermic reaction if you are removing heat,it will shift reaction to left at low temperature)

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