You will conduct the following three reactions in this experiment. In the space
ID: 505028 • Letter: Y
Question
Explanation / Answer
NaOH(aq) + HCl(aq) -----------> NaCl(aq) + H2O (l) H = -55.84 kJ/mol
NaOH(aq) + NH4Cl(aq) ---------> NH3(g) + H2O(l) + NaCl(aq) H = 30.56 kJ/mol
HCl(aq) + NH3(aq) ----------> NH4Cl(aq) H = -51.66 kJ/mol
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