a) Write the net ionic equations for Reactions 1, 2 and 3. Reaction 1 : Solid so

Question

a) Write the net ionic equations for Reactions 1, 2 and 3.

Reaction 1: Solid sodium hydroxide dissolves in water to form an aqueous solution of ions.

   NaOH(s) Na+(aq) + OH-(aq) + x1 kJ

Reaction 2: Solid sodium hydroxide reacts with an aqueous solution of hydrogen chloride to form water and an aqueous solution of sodium chloride.

   NaOH(s) + H+(aq) + Cl-(aq) H2O(l) + Na+(aq) + Cl-(aq) + x2 kJ

Reaction 3: An aqueous solution of sodium hydroxide reacts with an aqueous solution of hydrogen chloride to form water and an aqueous solution of sodium chloride.

   Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) H2O(l) + Na+(aq) + Cl-(aq) + x3 kJ

b) The energy, x1, in Reaction 1 represents the energy of solution for one mole of NaOH(s). Look at the net ionic equations for Reactions 2 and 3, and make a similar statement concerning the significance of x2 and x3.

X1 = -51.05

X2 = -115.54

X3 = -2.58

Explanation / Answer

Part-A) net ionic equations are:-

1. NaOH(s)<=>Na+(aq)+OH-(aq)

2. NaOH(s)+H+(aq)=H2O(l)+Na+(aq)

3. H+(aq)+OH-(aq)=H2O(l)

Part-B)

X2 represent energy of neutralisation of NaOH(S).

X3 represent neutralisation enthalpy of solution of NaOH

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.