HW-I Conc Units S17 ENVE 4408/5508: Water and Wastewater Quality Problem set No.
ID: 504133 • Letter: H
Question
HW-I Conc Units S17 ENVE 4408/5508: Water and Wastewater Quality Problem set No. 1: Concentration Units Atomic mass: Na 22.99, C 12.01:O 6.00: H 1.01; C1 35.45; P 30.97 (Report the concentrations at least 4 significant figures.) 1. (Sato) Make the following solutions; that is, convert the unit fromN (eq/L tomg/L. a) ILof 0.02-N NazCO3 solution. Note: NavCO3 CO3 2H CO3 b) 1 L of 0.02-N HCl solution. Note: HC1 H CI 2. (Sato. Calculate the concentrations of the following solutions in M (mol/L 01 mg/L Na2HPOa b) 1 mg/L HJPO4 c) l mg L NaH2PO4 3. (Sato) A 18 litters of simulated groundwater was prepared by adding reagent-grade salts to deionized water as follows: 0.0995 g of MgSOL, 0.1235 gofCaCl, 0.1865g of Naci, and 0.3033 g NaHCO3. What would be the result of the chemical analysis of this water? a)(20 pts) Complete the table attached Table 1)below. b)(5 pts) Check ion balance. Ission balance OK? c) (15 pts) Draw a bar graph for this water. (ENVE 5508 students draw a StifTDiagram also.) Note: Arrange cations in an order (sequence) of Ca' ,Mg Na ,K Amange anions in an order (sequence) of OH,CO3 r, HCOs ,SOs 3, CI ,NOsExplanation / Answer
1)
1 L of 0.02 N Na2CO3
0.02 N = equivalents of solute / L of solution
0.02 N = equivalents of solute / 1 L
equivalents of solute = 0.02
No. of moles of Na2CO3 = 0.02 /2 = 0.01 moles
Molar mass of Na2CO3 = 106 g/mol
mass of Na2CO3 = No. of moles * Molar mass = 0.01 moles * 106 g/mol = 1.06 g = 1060 mg
Concentration = 1060 mg / 1 L = 1060 mg/L
1 L of 0.02 N HCl
0.02 N = equivalents of solute / L of solution
0.02 N = equivalents of solute / 1 L
equivalents of solute = 0.02
No. of moles of HCl = 0.02 /1 = 0.01 moles
Molar mass of HCl = 36.44 g/mol
mass of Na2CO3 = No. of moles * Molar mass = 0.02 moles * 36.44 g/mol = 0.7288 g = 728.8 mg
Concentration = 728.8 mg / 1 L = 728.8 mg/L
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