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atalie T Long Indiana University of pe X ms/mod/ibis/view.php?id-3164326 3/30/20

ID: 503789 • Letter: A

Question

atalie T Long Indiana University of pe X ms/mod/ibis/view.php?id-3164326 3/30/2017 11:55 PM 20/100 Periodic Table stion 7 of 15 Sapling Learning At a given temperature, the elementary reaction A in the forward direction is first order in A with a rate constant of 260 x102 s The reverse reaction is first order in Band the rate constant is 5.80 x 102 s What is the value of the equilibrium constant for the reaction A B at this temperature? What is the value of the equilibrium constant for the reaction B A at this temperature F

Explanation / Answer

For A <----------> B

Equilibrium constant, Kc = Kf / Kr = 2.60 X 10-2 / (5.80 X 10-2) = 0.448

Now when you reverse the equilibrium reaction Kc gets inversed ,

so for reaction B <---------> A

Equilibrium constnat,Kc = 1 / 0.448 = 2.232