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Question

Question 3 of 3 rect Incorrect Incorrect Incorrect Incorrect Incorrect a: Incomect a: Incorect Sapling Learning this question has been by Pamela Mills at City University of New York (CUNY.Lehman Colle Map A What's the boiling point water at the top of Mt Everest (atmospheric pressure atm)? Thermodynamic Table at 250cc AHM S Substance (k J/mol) H,O H20(I) -285.8 70.0 -237.1 -241.8 188.8 -228.6 H20(g) Number Tb 25.82 Tne standard change in Gibbs energy for a reaction is o C EnAG (products EmbGr (reactants) AG. where AG is the standard molar Gibbs energy of formation, and n and m are coefficients from the chemical reaction. Previous 8 Give Up & View solution Try Again Next HExit partners privacy policy terms use contra us hep of

Explanation / Answer

Given reaction H2O (l) <----------> H2O (g)

Horxn = Hof of products - Hof of reactants

= -241.8 kJ/mol - (-285.8 kJ/mol)

= 44 kJ/mol

= 44000 J/mol

Horxn = Hvap = 44000 J/mol

Boiling point : The temperature at which vapor pressure of liquid is equal to atmospheric pressure.

Clasius-Claperyon equation is

In(P2/P1) = [Hvap/R] [(1/T1) - (1/T2)] ----- Eq(1)

where R = universal gas constant = 8.314 J/K/mol

T1 = Normal boiling point of water = 100 oC = 100 + 273 K = 373 K

T2 = ?

P1 = 1 atm

P2 = atmospheric pressure = 0.54 atm

Hvap = 44000 J/mol

Substitute all the values in eq (1) i.e.

In(P2/P1) = [Hvap/R] [(1/T1) - (1/T2)]

   In (0.54/1) = [44000 J/mol /8.314 J/K/mol] [(1/373) - (1/T2)]

On simplification,

T2 = 357.5 K

T2 = 357.5 - 273 oC

= 84.5 oC

Therefore,

boiling point of water at the top of Mt.Everest = 84.5 oC

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