I need help with my hw. 13-16 I actually got them wrong my 1st try. 13. What is
ID: 503343 • Letter: I
Question
I need help with my hw. 13-16 I actually got them wrong my 1st try.
Explanation / Answer
Q13.
find pH for:
V = 30 mL of M = 0.01 M acetic acid
V = 30 mL of M = 0.0075 M of acetate
Note that this will become a buffer
since
weak acid ( acetic acid) is present AND
conjugate base ( acetate ion ) will be present as well from the dissociation of Sodium Acetate
therefore, the equation we must use:
Henderson Hasselbach equation
pH = pKa + log(Acetate/Acetic Acid)
the pKa, from data tables is 4.75
so
pH = 4.75 + log(Acetate/Acetic Acid)
note that
we must recalculate final concentrations
Vtotal = V1+V2 = 30+30 = 60 mL
[Acid] = M1*V1/(Vtotal) = 30*0.01/60 = 0.005 M
[Acetate] = M2*V2/(Vtotal) = 30*0.0075/60 = 0.00375 M
substitute
pH = 4.75 + log(Acetate/Acetic Acid)
pH = 4.75 + log(0.00375 /0.005 )
pH = 4.6250
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