1)What is the pH of a solution prepared by mixing 20.0ml of 0.6M acetic acid (Ka

Question

1)What is the pH of a solution prepared by mixing 20.0ml of 0.6M acetic acid (Ka=1.8x10^-5) with 10ml of 1.0M NaOH? Report your answer to two decimal places.

2)What is the pH of a solution prepared by mixing 20ml of 0.6M acetic acid with 16ml of NaOH? Report your answer to two decimal places.

pH of a Weak Acid-Strong Base Solution Part A What is the pH of a solution prepared by mixing 20.0 mL of 0.6 M acetic acid (Ka 1.8 x 10 6) with 10 mL of 1.0 M NaoH? Report your answer to two decimal places. Submit My Answers Give U Part B What is the pH of a solution prepared by mixing 20.0 mL of 0.6 M acetic acid with 16 mL of NaoH? Report your answer to two decimal places. Submit My Answers Give Up Provide Feedback Continue

Explanation / Answer

mmoles of acetic acid = 20ml*0.6M = 12mmoles

mmoles of NaOH = 10ml*1.0M = 10mmoles

CH3COOH + NaOH ---> CH3COONa + H2O

Initial: 12mmoles 10mmoles 0 0

Change: -10mmoles -10mmoles +10

Equilbrm: 2mmoles 0 10

[CH3COOH] = 2mmoles

[CH3COONa] = 10mmoles

Ka = 1.8*10-5

pKa = -log(Ka) = -log(1.8*10-5) = 4.74

pH = pKa + log[conjugate base/acid]

pH = 4.74 + log(10/2)

pH = 4.74 + log5

pH = 5.44

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