Question 3 (8 pts) 1) The specificity of an exoglycosidase (enzyme that cleaves

Question

Question 3 (8 pts) 1) The specificity of an exoglycosidase (enzyme that cleaves the non-reducing residue of a polysaccharide chain) was tested on several substrates. The structure of the substrate (a to is shown below. Note that: G N-acetyl glucosamine, M-mannose, and Gr reduced N- acetylglucosamine a G SM b CG C G d CG h a SOM GM :DM f a i G Me One mole of N-actylglucosamine is released after treatment of a, b, g or h with this enzyme. Two moles of N-actylglucosamine are released after treatment of molecules e and f. The enzyme does not modify molecules c, d, and i. Determine the specificity of the enzyme. Be as precise as possible. (6pts) 2) How many moles of N-actylglucosamine are released after treatment of molecules j and k? (2 pts) DM k M at 3 M

Explanation / Answer

The exoglycosidase is an enzyme that release particular monosaccharide from non-reducing termini of oligosaccharide or polysaccharide. These enzymes show glycon specificity, which means they are substrate specific.

The exoglycosidase is the enzyme that cleaves non-reducing residue of the polysaccharides to release monosaccharides. In the given information, the N-acetyl glucosamine that is linked to mannose with 12 linkage is only released. The 1st carbon of N-acetyl glucosamine and 2nd carbon of mannose are involved in the linkage.

When j and k molecules are treated with enzyme called exoglycosidase then it releases one N-acetyl glucosamine each from two molecules.

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