What is the reduction half-reaction for the reaction of zinc with hydrochloric a

Question

What is the reduction half-reaction for the reaction of zinc with hydrochloric acid? Zn(s) + 2H^+ (aq) + 2CI^- (aq) rightarrow Zn^2+ (aq) + 2CI^- (aq) + H_2(g) a. Zn(s) rightarrow Zn^2+(aq) + 2e^- b. Zn(s)rightarrow Za^2+(aq) + 2CI^-(aq) + 2e^- c. + 2H^+(aq) + 2e^- rightarrow H_2(g) d. 2H^+(aq) + 2e^- + 2CI^- (aq) rightarrow H_2(g) + 2CI^- (aq) e. 2H^+(aq) + 2e^-(aq) rightarrow H_2(g) + 2CI (aq) When the following equation is balanced using the smallest possible integers, what is the number front of the substance in bold type? NaS_2O_3 + I_2 rightarrow Na_2S_4O_6 a. 1 b. 2 c. 3 d. 4 e. 6 When table sugar is burned in air, carbon dioxide and water vapor are products, as shown following unbalanced chemical equation: C_12H_22O_11(s) + O_2(g) rightarrow CO_2(g) + H_2O(g) How many moles of oxygen are required to react completely with 1.26 mol of sugar? a. 15.1 b. 1.26 c. 22 d. 30 e. none of these An aqueous solution of potassium sulfate is allowed to react with an aqueous solution nitrate. What is the coefficient of the solid in the balanced equation (in standard form)? a.1 b. 2 c. 3 d. 4 e. 6

Explanation / Answer

Answer 11. (c) 2H +(aq) + 2e H2 (g)

Answer 12. (b) 2

2 Na2S2O3 + I2 --- 2 NaI + Na2S4O6 (After balancing)

Answer 13. Balancing the equation: C12H22O11(s) + 12 O2(g) --> 12 CO2(g) + 11 H2O(g)

So, the ratio between C12H22O11 : O2 =1:12,

Therefore moles of O2 required is 1.26 * 12 = 15.1 (a).

Answer 14. (a) 1.

K2SO4 + Ba(NO3)2 -- BaSO4 (s) + 2KNO3 (aq)

Here 2KNO3 exists in ionic form K+ and NO3- ions, and BaSO4 is a solid precipitate.

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.