1. What is the heat capacity in J/C of a sample of water that contains 16.8 g of

Question

1. What is the heat capacity in J/C of a sample of water that contains 16.8 g of water?

2. 50.0 g hot water at 60.0 C was mixed with 50.0 g cold water at 20.0 C. If the final temperature is 36.4, what is the heat capacity of the calorimeter?

3. in Calibration step (part I), a student recorded all temperatures for 3 min after the two water samples were combined in calorimeter. The temperature first increased, then slowly leveled off and then start to decrease by 2 min. If the student used the temperature at 3-min mark as his final temperature, his calculated heat capacity of calorimeter will be:

Explanation / Answer

1)
specific heat capacity of water = 4.184 J/goC

heat capacity = mass * specific heat capacity
= 16.8 g * 4.184 J/goC
= 70.29 J/oC

Answer: 70.3 J/oC

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