A titration involves adding a reactant of known quantity to a solution of an ano

Question

A titration involves adding a reactant of known quantity to a solution of an another reactant while monitoring the equilibrium concentrations. This allows one to determine the concentration of the second reactant. The equation for the reaction of a generic weak acid HA with a strong base is HA(aq)+OH(aq)A(aq)+H2O(l) A certain weak acid, HA, with a Ka value of 5.61×106, is titrated with NaOH.

Part A) A solution is made by titrating 9.00 mmol (millimoles) of HA and 2.00 mmol of the strong base. What is the resulting pH?

Part B) More strong base is added until the equivalence point is reached. What is the pH of this solution at the equivalence point if the total volume is 43.0 mL ?

Explanation / Answer

HA is weak acid with Ka = 5.61× 10 ^-6

Titration is HA vs NaOH , molarity of HA is 9 mili moles

Therefore [H ^+ ] = Ka × C

C = 9 × 10^-3 ( mili moles to deci moles )

[ H^+ ] = 5.61 × 10^-6 × 9 × 10 ^ -3

= 22.47 × 10^ -5

pH = - log [ H^+ ]

- log 22.47 × 10^-5 = 3.6481

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