SOS please show your work for each section so I can understand how to do this. T

Question

SOS please show your work for each section so I can understand how to do this. THANKS

The combustion of glucose:C_6H_12O_6(g) + 6O_2(g) rightarrow 6CO_2(g) + 6H_2O(g) has a reaction enthalpy of delta H_ = 2803 kJ. How much heat is given off when 331 g of glucose is burned in excess oxygen? molar masses: C_6H_12O_6 = 180.2, O_2 = 32.00, CO_2 = 44.01, H_2O = 18.01 Aluminum metal will react with strong acids to dissolve the aluminum and produce hydrogen gas. The answer for each part this question is needed for the part that follows; if the preceding part is incorrect, the succeeding parts will not be graded. a. Write the balanced net ionic equation, including phases, for the reaction of aluminum metal with nitric b. 10.00 g of aluminum metal are reacted with 100.0 ml of 10.0 M nitric acid. How many ml of hydrogen gas will be collected above the nitric acid solution at a temperature of 27 degree C and a pressure of 772 torr? The vapor pressure of water at this temperature is 26.7 torr. c, If there are any reactants left over after the reaction competes, indicate their amounts below. If none are left, enter zero for that reactant: grams aluminum left over: final concentration (M) of nitric acid:

Explanation / Answer

moles of glucose = 331 / 180.2 = 1.837

C6H12O6 + 6 O2   -----------------> 6 CO2 + 6 H2O

delta Hrxn = - 2803 kJ

delta H = - Q / n

1 mol glucose ----------------> - 2803 kJ

1.837 mol glucose --------------->   ??

heat = 1.837 x 2803 / 1

        = 5148.7 kJ

heat given off = 5149 kJ

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