1. Review Experiments 3, 5, 6, and 7 2. Read carefully the to Adhere\" for Labor
ID: 497982 • Letter: 1
Question
1. Review Experiments 3, 5, 6, and 7 2. Read carefully the to Adhere" for Laboratory Practical 1. 3. Set up your notebook with objectives, materials, and a clear scheme (flowchart) of the procedure. Turn in this preliminary work stapled to the back of the procedure you will turn in to your TA. 4. Prepare a step-by-step procedure based on the scheme you have written. Procedures written in a paragraph form will not be graded! 5. You must include in the procedure the of the grams of each hydrate needed to prepare the solutions. Do not include any calculations!Explanation / Answer
Part-1
Moles of CuSO4*5H2O = M x V = 0.500 x 0.0500 L = 0.025
Molar mass CuSO4 5H2O = 63.55 (Cu) + 32.07 (S) + 4 × 16.00 (O) + 5 × [2 × 1.01 (H) + 16.00 (O)]
= 249.72 g /mol
Weight of CuSO4 5H2O = 0.025 mol x 249.72 g/mol = 6.243g
Prepare exactly 50.0 mL of aqueous 0.500 M CuSO4 solution from solid CuSO4 ·5H O,
In a beaker add exactly 6.243 grams of CuSO4 ·5H O.
Add 50mL of water to the beaker, using a stirring rod, stir the mixture until all of the
CuSO4.5H2O crystals have dissolved.
Part 2)
Prepare exactly 50.0 mL of aqueous 0.300 M Ca(NO3)2 from solid Ca(NO3)2·4H2O.
Moles of Ca(NO3)2·4H2O. = M x V = 0.300 x 0.0500 L = 0.015
Molar mass of Ca(NO3)2*4H2O is 236.1489 g/mol
Weight of Ca(NO3)2·4H2O = 0.015 mol x 236.1489 g/mol = 3.54g
In a beaker add exactly 3.54grams of Ca (NO2)3.4H2O Add 50mL of water to the beaker, using a stirring rod, stir the mixture until all of the crystals have dissolved.
Mol of CuSO4 in the solutions = 0.500 x 0.0500 L = 0.025 moles
Mass of CuSO4 = 159.61g/mol x 0.025 mol = 3.99 g
Molar mass of Ca (NO2)3 is 178.0945 g/mol
Mass of Ca(NO2)3 = 0.015mol x 178.0945 g/mol = 2.46 grams
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