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1. Review Experiments 3, 5, 6, and 7 2. Read carefully the to Adhere\" for Labor

ID: 497982 • Letter: 1

Question

1. Review Experiments 3, 5, 6, and 7 2. Read carefully the to Adhere" for Laboratory Practical 1. 3. Set up your notebook with objectives, materials, and a clear scheme (flowchart) of the procedure. Turn in this preliminary work stapled to the back of the procedure you will turn in to your TA. 4. Prepare a step-by-step procedure based on the scheme you have written. Procedures written in a paragraph form will not be graded! 5. You must include in the procedure the of the grams of each hydrate needed to prepare the solutions. Do not include any calculations!

Explanation / Answer

Part-1

Moles of CuSO4*5H2O   = M x V = 0.500 x 0.0500 L = 0.025

Molar mass CuSO4 5H2O = 63.55 (Cu) + 32.07 (S) + 4 × 16.00 (O) + 5 × [2 × 1.01 (H) + 16.00 (O)]

= 249.72 g /mol

Weight of CuSO4 5H2O = 0.025 mol x 249.72 g/mol = 6.243g

Prepare exactly 50.0 mL of aqueous 0.500 M CuSO4 solution from solid CuSO4 ·5H O,

In a beaker add exactly 6.243 grams of CuSO4 ·5H O.

Add 50mL of water to the beaker, using a stirring rod, stir the mixture until all of the

CuSO4.5H2O crystals have dissolved.

Part 2)

Prepare exactly 50.0 mL of aqueous 0.300 M Ca(NO3)2 from solid Ca(NO3)2·4H2O.

Moles of Ca(NO3)2·4H2O. = M x V = 0.300 x 0.0500 L = 0.015

Molar mass of Ca(NO3)2*4H2O is 236.1489 g/mol

Weight of Ca(NO3)2·4H2O = 0.015 mol x 236.1489 g/mol = 3.54g

In a beaker add exactly 3.54grams of Ca (NO2)3.4H2O Add 50mL of water to the beaker, using a stirring rod, stir the mixture until all of the crystals have dissolved.

Mol of CuSO4 in the solutions = 0.500 x 0.0500 L = 0.025 moles

Mass of CuSO4 = 159.61g/mol x 0.025 mol = 3.99 g

Molar mass of Ca (NO2)3 is 178.0945 g/mol

Mass of Ca(NO2)3 = 0.015mol x 178.0945 g/mol = 2.46 grams