At a certain temperature, the solubility product constant of copper (II) iodate,

Question

At a certain temperature, the solubility product constant of copper (II) iodate, Cu(lO_3)_2, is 8.28 times 10^-8 M^3. Calculate the solubility of this compound for this temperature. Unless stated otherwise all solubility product constants are for water. Answer: Calculate the solubility of copper (II) iodate in 0.65 M copper (II) nitrate. K_sp is 7.4 times 10^-8 M^3. You should know that the K_sp must refer to the copper iodate because all nitrate compounds are soluble and strong electrolytes! Answer:

Explanation / Answer

19)

Cu(IO3)2   <-----> Cu2+   +   2 IO3-
                                     s                 2s

Ksp = [Cu2+][IO3-]^2
Ksp = s * (2s)^2
8.28*10^-8 = 4*s^3
s = 2.75*10^-3 M

Answer: 2.75*10^-3 M

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