17. Why would NaCN be basic 18. Why would KNO3 would be neutral A) H2 B) H2S C)
ID: 497625 • Letter: 1
Question
17. Why would NaCN be basic 18. Why would KNO3 would be neutral A) H2 B) H2S C) H2Se (D) H2Te E) not enough information is available 17. Which of the following 0.10 M aqueous solution will be basic? A) NH4CIO4 GB NacN C) KNO3 D)H2C204 E) all are acidic or neutral 18. Which of the following 0.10 M aqueous solutions will be neutral? A) NH4CIO4 B) NaCN C) KNO3 D)H2C204 E) all are acidic or basic (24 pts)The following reaction has a Kc of 620. at a certain temperature. Calculate equilibrium concentrations of all species if 4.50 mol of each chemical in the reaction re added to a 3.00 L flask.Explanation / Answer
17.Aqueous solution of NaCN :
Sodium cyanide react with water to produce sodium hydroxide and hydrogen cyanide.
NaCN(aq) + H2O(l) ----------> NaOH (aq) + HCN(aq)
Where NaOH is strong base and HCN is weak acid.
Due to this the entire solution acts as a base.
Whereas NH4ClO4 on hydrolysis forms a strong acid HClO4 and weak base NH4OH.
KNO3 also on hydrolysis forms KOH (strong base) and a strong acid.
Hence the solution is neutral.
Oxalix acid H2C2O4 is a weak acid.
18. Aqueous solution of KNO3:
KNO3(aq) + H2O(l) ----------> HNO3 (aq) + KOH(aq)
Where KOH is strong base and HNO3 is a strong acid.
Due to this the entire solution acts as neutral.
Whereas NH4ClO4 on hydrolysis forms a strong acid HClO4 and weak base NH4OH.
Sodium cyanide react with water to produce sodium hydroxide and hydrogen cyanide.
Where NaOH is strong base and HCN is weak acid.
Due to this the entire solution acts as a base.
Oxalix acid H2C2O4 is a weak acid.
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