Which of the following is the most effective buffer system for a pH value of 4.4
ID: 496700 • Letter: W
Question
Which of the following is the most effective buffer system for a pH value of 4.45?
H2CO3/HCO3– (Ka1 for H2CO3 is 4.3 × 10–7.)
HCO3–/CO32– (Ka2 for H2CO3 is 4.8 × 10–11.)
H2S/HS– (Ka1 for H2S is 8.9 × 10–8.)
HC2O4–/C2O42– (Ka2 for H2C2O4 is 5.1 × 10–5.)
H3PO4/H2PO4– (Ka1 for H3PO4 is 6.9 × 10–3.)
A.H2CO3/HCO3– (Ka1 for H2CO3 is 4.3 × 10–7.)
B.HCO3–/CO32– (Ka2 for H2CO3 is 4.8 × 10–11.)
C.H2S/HS– (Ka1 for H2S is 8.9 × 10–8.)
D.HC2O4–/C2O42– (Ka2 for H2C2O4 is 5.1 × 10–5.)
E.H3PO4/H2PO4– (Ka1 for H3PO4 is 6.9 × 10–3.)
Explanation / Answer
For most effective buffer system
pH value is close to pKa value.
So option C is answer.
Since pKa of bicarbonate anion = -log(5.1 × 10^-5)
= 5 - log(5.1) = 5 - 0.7 = 4.3
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