Write the equilibrium constant expression for the following reaction and determi

Question

Write the equilibrium constant expression for the following reaction and determine the value of the equilibrium constant for the reaction using appropriate equilibrium constants from the Appendices found at the back of the Harris text:

PbI2 (s) + S2- (aq) <----> PbS (s) + 2 I- (aq)

Please help! I haven't been able to find the actual eq. constant values on the back of the book or on the web.

The equilibrium constant expression I wrote is:

Kc = [I-]^2 / [S2-]

Is it correct? And please provide the appropriate equilibrium constants from a (any) book Appendix so I have an idea of what to look for in the book. Thank you!

Explanation / Answer

Given equilibrium reaction is PbI2 (s) + S2-(aq) <----> PbS (s) + 2 I- (aq)

Equilibrium constant , Kc = ([PbS(s)] [I- (aq)]2 ) / ([PbI2 (s)][S2- (aq)])

Since the concentration of solids will not change , so the equilibrium constant will not effect so

[PbI2 (s)] = [PbS(s)]=1

Then Kc becomes Kc = (1x [I- (aq)]2 ) / (1x[S2- (aq)])

   Kc = [I- (aq)]2 / [S2- (aq)]

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