Manganese(II) sulfide, MnS, dissociates in water according to the chemical equat

Question

Manganese(II) sulfide, MnS, dissociates in water according to the chemical equation below. The solubility product constant is 3.0 x 10–14.

MnS(s) + H2O(l) Mn2+(aq) + HS– (aq) + OH– (aq)

Consider that you add KOH(aq) to the system. How will this addition affect the solubility of MnS(s) in water?

a. The MnS solubility will be unchanged.

b. The MnS solubility will decrease.

c. The MnS solubility will increase.

d. The exact amount of added KOH must be known before a reliable prediction can be made.

e. The pKa of H2S is needed before a reliable prediction can be made.

Explain.

Explanation / Answer

koh is added to the to the system the equilibrium shift towards left and adding koh increses the concentration of oh- on the right side i.e common ion is oh-

so the solubilty of Mns will decrease

answer is = b

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